7x^2+7=700

Solution for 7x^2+7=700 equation:

7x^2+7=700

We move all terms to the left:

7x^2+7-(700)=0

We add all the numbers together, and all the variables

7x^2-693=0

a = 7; b = 0; c = -693;
Δ = b2-4ac
Δ = 02-4·7·(-693)
Δ = 19404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{19404}=\sqrt{1764*11}=\sqrt{1764}*\sqrt{11}=42\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-42\sqrt{11}}{2*7}=\frac{0-42\sqrt{11}}{14}
=-\frac{42\sqrt{11}}{14}
=-3\sqrt{11}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+42\sqrt{11}}{2*7}=\frac{0+42\sqrt{11}}{14}
=\frac{42\sqrt{11}}{14}
=3\sqrt{11}
$